Betterhalfgujaratimoviefreedownload Fix 📦

Betterhalfgujaratimoviefreedownload Fix 📦




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A string that contains a little-endian UTF-16 string

I need to make a string that contains a little-endian UTF-16 string, just like this one (which is in big-endian):
const char *tuple = “This is just a little-endian UTF-16 string\0”

In the above string, the “\0” is the NULL symbol (\u0000). I’m expecting to get this string by the following expression:
struct utf16string* utf16String = malloc(utf16string);
memcpy(utf16String->string, tuple, utf16string->length);

But this won’t work, because the “\0” is the 0 symbol and, of course, the 0 symbol is bigger than the “U” symbol (\u0080). I’d like to know if there’s a way to get my little-endian string.


You can do this in two parts:

store the string in raw bytes without conversion, and
store it with all the null bytes converted to UTF-16 escape sequences (the byte order marks).

For the first, you can simply use strcpy(). For the second, you can use normal UTF-16 decoding to reverse this process.
This should suffice:
char *utf16String = malloc(utf16string);
char *p = strcpy(utf16String, tuple);
while(p length) {
char b = *p;
if(b & 0xC0 == 0x80)
b = *p;
*utf16String++ = (b >> 6) | 0xF4;
*utf16String++ = (b & 0x3F) | 0x80;
*utf16String = 0;

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